Asked by yeah
A rocket-powered hockey puck has a thrust of 4.70 N and a total mass of 2.40 kg. It is released from rest on a frictionless table, 4.80 m from the edge of a 3.00 m drop. The front of the rocket is pointed directly toward the edge.
How far does the puck land from the base of the table?
How far does the puck land from the base of the table?
Answers
Answered by
bobpursley
How long does the rocket fire in time...I assume the entire trip.
F=ma a=4.7/2.4
time to get to the edge:
4.8=1/2 a t^2
t= sqrt 9.6*2.4/4.7 = 2.21sec
time to drop:
t=sqrt(1/2 g *3)=3.83 sec
Velocity at edge= sqrt(2.21*4.7/2.4)=2.08m/s
distancefrom table= vi*t+1/2 at^2
where t is the time to drop
= 2.08*3.83+1/2*4.7/2.4*3.83^2
and you can compute that, check it all.
F=ma a=4.7/2.4
time to get to the edge:
4.8=1/2 a t^2
t= sqrt 9.6*2.4/4.7 = 2.21sec
time to drop:
t=sqrt(1/2 g *3)=3.83 sec
Velocity at edge= sqrt(2.21*4.7/2.4)=2.08m/s
distancefrom table= vi*t+1/2 at^2
where t is the time to drop
= 2.08*3.83+1/2*4.7/2.4*3.83^2
and you can compute that, check it all.
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