Question
the distance between any two bases on a baseball diamond is 90 feet.What is the best approximation for the direct distance from home plate to second base?
A baseball diamond's four bases form a square with 90 foot sides. A right triangle is formed by home plate, first and second base. The distance from second base to home is the hypotenuse of that triangle.
Apply the Pythagorean theorem
a^2 + b^2 = c^2 to the right triangle and you will have the answer. In this case, a = b = 90. Solve for c.
A baseball diamond's four bases form a square with 90 foot sides. A right triangle is formed by home plate, first and second base. The distance from second base to home is the hypotenuse of that triangle.
Apply the Pythagorean theorem
a^2 + b^2 = c^2 to the right triangle and you will have the answer. In this case, a = b = 90. Solve for c.
Answers
this is not the question i was looking for!!! >.<
i wanted a related rates question!!!!!!
i have a test on it!!!!!
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i wanted a related rates question!!!!!!
i have a test on it!!!!!
omg ><
127.28
Which statement is true about the following pair of triangles?
Square with one side 30 am done side 60 and a smaller square one side 6 and one side 3
Square with one side 30 am done side 60 and a smaller square one side 6 and one side 3
93 ft
this was literally posted before i was born
d^2 = a^2 + b^2.
a=90, b=90
d^2 = 90^2 + 90^2 >>> d^2 = 2 * 90^2
d = 90 sq.rt.2 ft.
a=90, b=90
d^2 = 90^2 + 90^2 >>> d^2 = 2 * 90^2
d = 90 sq.rt.2 ft.
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