Asked by Morgan
determine the molarity of a solution of silver nitrate prepared by dissolving 5g of silver nitrate in 25.0mL of water
Answers
Answered by
DrBob222
mols AgNO3 = grams/molar mass
Then M = mols/L solution.
Technically this problem can't be worked because the definition is mols/L SOLUTION and when you put 5.0 g AgNO3 in 25.0 mL water that DOESN'T make 25.0 mL solution but the solution volume is slight more than 25.0 mL. When someone makes up a problem like this, if they quote it as above then the density of the solution should be stated and you get the volume of the solution from the density of the solution and the mass of the solution.
Then M = mols/L solution.
Technically this problem can't be worked because the definition is mols/L SOLUTION and when you put 5.0 g AgNO3 in 25.0 mL water that DOESN'T make 25.0 mL solution but the solution volume is slight more than 25.0 mL. When someone makes up a problem like this, if they quote it as above then the density of the solution should be stated and you get the volume of the solution from the density of the solution and the mass of the solution.
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