Asked by Wade
determine the new molarity of calcium ions when 50.0 mL of a 1.50 M calcium chloride solution are combined with 750.0 mL of a 0.236 M calcium phosphate solution.
Answers
Answered by
DrBob222
moles CaCl2 = M x L = ??
moles Ca^+2 = same
moles Ca3(PO4)2 = M x L = ??
moles Ca^+2 = 3x that.
Assuming the volumes are additive,
M = total moles/total volume.
moles Ca^+2 = same
moles Ca3(PO4)2 = M x L = ??
moles Ca^+2 = 3x that.
Assuming the volumes are additive,
M = total moles/total volume.
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