Question

Prove:sin ^2(7π/8)+sin^2(5π/8)+sin^2(3π/8)+sin^2(π/8)=0

Answer 1

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Answer 2

Since sin(π-x) = sin(x),

sin 7π/8 = sin π/8
sin 5π/8 = sin 3π/8

But your equation is clearly false, since all those sin^2 are positive, so they cannot add to zero.