Asked by edward
                find the centroid of the area of the finite region enclosed by the curve y=x^(2)+1, when x-axis and the line, x=0 and x=3
            
            
        Answers
                    Answered by
            Steve
            
    Just use the formula. The x-coordinate is
∫[0,3] xy dx = ∫[0,3] x^3+x dx
-------------------------------------
∫[0,3] y dx = ∫[0,3] x^2+1 dx
∫[0,3] x^3+x dx
-------------------
∫[0,3] x^2+1 dx
Then do the same for y, using x = √(y-1) since we are in the first quadrant.
    
∫[0,3] xy dx = ∫[0,3] x^3+x dx
-------------------------------------
∫[0,3] y dx = ∫[0,3] x^2+1 dx
∫[0,3] x^3+x dx
-------------------
∫[0,3] x^2+1 dx
Then do the same for y, using x = √(y-1) since we are in the first quadrant.
                    Answered by
            edward
            
    but steve i don,t know it dat is why i posted it so that i can gt help from you guys to help me study further 
    
                    Answered by
            Steve
            
    If you do not understand the integral equations, you have a long way to go, namely calculus. Go pick up any 1st-year calculus book, and somewhere in its index you will find how to determine the centroid of a curved area. Google will also help, with many examples, but unless you have picked up come calculus, they will be incomprehensible.
    
                    Answered by
            edward
            
    ok thanks steve,i will do just dat 
    
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