Asked by Anonymous
A stone thrown vertically upwards from the top of a building takes 3s to reach its maximum height . Find
1. The velocity with which it is thrown
2.the maximum height it reaches above the builibg
Answers
Answered by
Damon
v = Vi - 9.81 t
0 = Vi - 9.81*3
so Vi = 29.4 m/s
m g h = (1/2) m v^2
so
v^2 = 2(9.81) h
29.4^2 = 19.6 h
h = 44.2 m
0 = Vi - 9.81*3
so Vi = 29.4 m/s
m g h = (1/2) m v^2
so
v^2 = 2(9.81) h
29.4^2 = 19.6 h
h = 44.2 m
Answered by
Ntombazanyane
Calculate the time taken for stone a to reach it's maximum height
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