Question

How many milliliters of .200 M NaOH solutions are needed to react with 40.0 mL of a 0.340 M NiCl2 solution?

Equation: NiCl2(aq) + 2NaOH(aq) --> Ni(OH)2(s) +2NaCl(aq)
mols NiCl2 = M x L = ?
mols NaOH = 2 x mols NiCl2.
M NaOH = mols NaOH/L NaOH. You know mols and M NaOH, solve for L and convert to mL.
1360 mL

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