Asked by oday
A particle (charge = +4.0 nC) is located on the x-axis at the point x = -20.0 m, and a second particle (charge = -10.0 nC) is placed on the x-axis at x=+8.0 m. What is the magnitude of the total electrostatic field (in N/C) at the origin (x=0)?
Answers
Answered by
Anonymous
Add the two components...
Et=E1+E1=k4/20^2+k10^2/8^2
negative sign points to minus x axis, so in this case, E is to the right
Et=E1+E1=k4/20^2+k10^2/8^2
negative sign points to minus x axis, so in this case, E is to the right
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