Question
A particle with a charge of -4.50x 10^-10 C and a mass of 6.6x 10^-18 kg is placed between two oppositely charged parallel plates with a voltage of 9.00x 10^5 V. The particle is injected at the negative plate with an initial speed of zero. What is the final speed of the particle just before it strikes the positive plate?
Answers
ΔKE = W (of electric field)
0 – mv^2/2 = qU
v=sqrt (2qU/m)
0 – mv^2/2 = qU
v=sqrt (2qU/m)
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