ΔKE = W (of electric field)
0 – mv^2/2 = qU
v=sqrt (2qU/m)
A particle with a charge of -4.50x 10^-10 C and a mass of 6.6x 10^-18 kg is placed between two oppositely charged parallel plates with a voltage of 9.00x 10^5 V. The particle is injected at the negative plate with an initial speed of zero. What is the final speed of the particle just before it strikes the positive plate?
1 answer