Asked by S
A particle of charge +18.1C and mass 7.06 × 10-5 kg is released from rest in a region where there is a constant electric field of +414 N/C. What is the displacement of the particle after a time of 3.06 × 10-2 s?
Please explain the steps, thank you.
Please explain the steps, thank you.
Answers
Answered by
Damon
calculate F = Q E
do a = F/m to get a, the acceleration
then plain old constant acceleration
x = (1/2) a t^2
do a = F/m to get a, the acceleration
then plain old constant acceleration
x = (1/2) a t^2
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