A particle of charge +18.1C and mass 7.06 × 10-5 kg is released from rest in a region where there is a constant electric field of +414 N/C. What is the displacement of the particle after a time of 3.06 × 10-2 s?

Question

Please explain the steps, thank you.

Answer 1

Damon answered
9 years ago

calculate F = Q E

do a = F/m to get a, the acceleration

then plain old constant acceleration
x = (1/2) a t^2