Asked by Aleeyah Lacuesta
A Chemist needs 200 liters of 30% acid solution. she has a 20% and 50% acid solution. How much of each must she mix?
Answers
Answered by
Reiny
amount of the 20% stuff --- x L
amount of the 50% stuff --- 200-x L
.2x + .5(200-x) = .3(200)
times 10
2x + 5(200-x) = 3(200)
2x + 1000 - 5x = 600
-3x = -400
x = 400/3
The chemist needs 400/3 L of the 20% solution and 200/3 L of the 50% solution
amount of the 50% stuff --- 200-x L
.2x + .5(200-x) = .3(200)
times 10
2x + 5(200-x) = 3(200)
2x + 1000 - 5x = 600
-3x = -400
x = 400/3
The chemist needs 400/3 L of the 20% solution and 200/3 L of the 50% solution
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.