Asked by Aleeyah Lacuesta
                A Chemist needs 200 liters of 30% acid solution. she has a 20% and 50% acid solution. How much of each must she mix?
            
            
        Answers
                    Answered by
            Reiny
            
    amount of the 20% stuff --- x L
amount of the 50% stuff --- 200-x L
.2x + .5(200-x) = .3(200)
times 10
2x + 5(200-x) = 3(200)
2x + 1000 - 5x = 600
-3x = -400
x = 400/3
The chemist needs 400/3 L of the 20% solution and 200/3 L of the 50% solution
    
amount of the 50% stuff --- 200-x L
.2x + .5(200-x) = .3(200)
times 10
2x + 5(200-x) = 3(200)
2x + 1000 - 5x = 600
-3x = -400
x = 400/3
The chemist needs 400/3 L of the 20% solution and 200/3 L of the 50% solution
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