Asked by Yakima
A chemist needs to mix an 18% acid solution with a 45% acid solution to obtain a 12 liter mixture consisting of 36% acid. How many liters of each acid solutions must be used?
Answers
Answered by
Reiny
amount of 18% solution --- x L
amount of 45% solution --- 12-x L
.18x + .45(12-x) = .36(12)
times 100
18x + 45(12-x) = 36(12)
take it from here
amount of 45% solution --- 12-x L
.18x + .45(12-x) = .36(12)
times 100
18x + 45(12-x) = 36(12)
take it from here
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