Question

A chemist has three different acid solutions. The first acid solution contains
25
%
acid, the second contains
35
%
and the third contains
55
%
. He wants to use all three solutions to obtain a mixture of
50
liters containing
45
%
acid, using
3
times as much of the
55
%
solution as the
35
%
solution. How many liters of each solution should be used?

Answer 1

why all those annoying newlines?
x+y+z = 50
z = 3y
.25x + .35y + .55z = .45*50
Now solve for x,y,z