Asked by Lucy
x^2 + 2x + 2 = 0
The answer has an imaginary number in it which we're supposed to solve for, but I'm having trouble with it.
Thanks for any help!
The answer has an imaginary number in it which we're supposed to solve for, but I'm having trouble with it.
Thanks for any help!
Answers
Answered by
Reiny
x^2 + 2x + 2 = 0
I would use "completing the square"
x^2 + 2x = -2
x2 + 2x + 1 = -2+1
(x+1) = -1
x+1 = ±√-1, remember √-1 = i
x = -1 ± i
I would use "completing the square"
x^2 + 2x = -2
x2 + 2x + 1 = -2+1
(x+1) = -1
x+1 = ±√-1, remember √-1 = i
x = -1 ± i
Answered by
aycee
(x^2 + 2x + 2) -1 = (0)-1
x^2 + 2x +1 = -1
(x + 1)(x + 1) = -1
(x +1)^2 = -1
(x +1) = sr(-1) (sr squareroot of)
x = -1 + sr(-1)
x^2 + 2x +1 = -1
(x + 1)(x + 1) = -1
(x +1)^2 = -1
(x +1) = sr(-1) (sr squareroot of)
x = -1 + sr(-1)
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