Asked by Steve

A model rocket is launched from a roof into a large field. The path the rocket can be modeled by the equation y=-0.04x^2+8.3x+4.3 where x is the horizontal distance in meters, from the starting point on the roof and y is the height in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?
Answered by Steve
my answer is 208.02 meters
Answered by Reiny
Since you want the distance horizontally from the starting point, you want y to be 4.3m which is the initial height, thus
0 = -.04x^2 + 8.3x
x(.04x - 8.3) = 0
x = 0 , which would be our starting point and
x = 8.3/.04 or 207.5 m

your answer would be the distance from a height of 4.3 m to the ground, which would not be a horizontal line
Answered by TomIsARat
yas
Answered by Anonymous
will some one please give the answers i’ve been sick for like a month and procrastinated math and did everything else but i learned nothing and i’m not even supposed to be in algebra and i need help
Answered by Person
The correct answer is 208.02 m
Answered by --Rest In Paradise--
@Anonymous ...same bruh
Answered by bruv
the answer is 208.02 m
Answered by the guy that has a random name
its 208.2
Answered by Amber Sugar
this site Is so ugly now lol
There are no AI answers yet. The ability to request AI answers is coming soon!