Asked by Haley
A 1.76g sample of quinone, C6H4O2, is burned in a calorimeter whose total heat capacity is 7.854 kJ/C. The temperature of the calorimeter increases from 23.44 C to 29.14 C. What is the heat of combustion per mole of quinone? The molar mass of quinone is 108.1 g/mol.
The answer is -2.75x10^3 kJ/mol but I just cant quite figure out how to get that! PLEASE HELP! Thank you!
The answer is -2.75x10^3 kJ/mol but I just cant quite figure out how to get that! PLEASE HELP! Thank you!
Answers
Answered by
DrBob222
0 = qcal + qcombustion
0 = Ccal*(delta T) + qcombustion
0 = 7854*delta T + qcomb
Solve for qcomb
Then q/mol = (qabove/1.76)*molar mass quinone
0 = Ccal*(delta T) + qcombustion
0 = 7854*delta T + qcomb
Solve for qcomb
Then q/mol = (qabove/1.76)*molar mass quinone
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