A 2.200-g sample of quinone (C6H4O2) was burned in a bomb calorimeter whose total heat capacity is 7.854 kJ/OC. The temperature of the calorimeter increases from 23.44 OC to 30.57 OC. What is the heat of combustion in kJ per mole quinone?

Answer 1

q = Ccal x dT = 7.854 kJ/oC x 23.44 oC = 184.1 kJ.
That's 184.1 kJ/2.2 g x 108 g/mol = ? kJ/mol
For combustion that usually is shown as a negative value.