Question

If a sample of C6H4(CH3)2 is found to contain 3.54 * 10^26 CH3 groups how many moles of C6H4(CH3)2 molecules are present?

C6H4(CH3)2 - 106.17
CH3 group - 15.035
C6H4 Group - 76.098

Please explain steps

Answer 1

3.54E26 CH3 groups x (1 molecule C6H4(CH3)2/2 CH3 groups) = ? molecules C6H4(CH3)2
Convert to moles with 6.022E23 molecules/mol.