Asked by Anonymous
I need help proving this identity
2sin^2x - 1 = sin^2x - cos^2x
2sin^2x - 1 = sin^2x - cos^2x
Answers
Answered by
Reiny
This one's really easy ...
RS = sin^2 x - cos^2 x
= sin^2 x - (1 - sin^2 x)
= 2sin^2 x - 1
= LS
RS = sin^2 x - cos^2 x
= sin^2 x - (1 - sin^2 x)
= 2sin^2 x - 1
= LS
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