Question
I need help proving this identity
2sin^2x - 1 = sin^2x - cos^2x
2sin^2x - 1 = sin^2x - cos^2x
Answers
Reiny
This one's really easy ...
RS = sin^2 x - cos^2 x
= sin^2 x - (1 - sin^2 x)
= 2sin^2 x - 1
= LS
RS = sin^2 x - cos^2 x
= sin^2 x - (1 - sin^2 x)
= 2sin^2 x - 1
= LS