Asked by Anonymous
I need help proving this identity
cscx + secx = (cosx + sinx)(secx)(cscx)
cscx + secx = (cosx + sinx)(secx)(cscx)
Answers
Answered by
Reiny
LS = 1/sinx + 1/cosx
= (cosx + sinx)/(sinxcosx)
= (cosx + sinx)(1/sinx)(1/cosx)
= (cosx+ sinx)(cscx)(sec)
= RS
= (cosx + sinx)/(sinxcosx)
= (cosx + sinx)(1/sinx)(1/cosx)
= (cosx+ sinx)(cscx)(sec)
= RS
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