Question

Consider a 6·kg disk with a radius of 0.6·m and rotating about an axis passing through its center.
(a) What is its rotational inertia? kg·m2

(b) Suppose the disk is rotating counterclockwise and slowing down with a rotational acceleration of 5·rad/s2. What is the net torque acting on the disk? N·m

(c) Suppose the torque you found for the last part is being produced by a force applied at a point 0.3·m from the axis. If the direction of the force is perpendicular to a line from the axis to that point, what is the magnitude of the force? N

Answer 1

Rotational inertia I=mr^2 while m is 6 kg and r is 0.6 m

B) torque =Ia while a is -5 rad/s