Calculate the electrical attraction that a proton in a nucleus exerts on an orbiting electron if the two particles are 1.13×10^-10 m apart.

Answer 1

Use Coulomb's Law:

F = k*Q1*Q2 / r^2

k = 9.00x10^9 N.m^2/C^2 (Coulomb's constant)
Q1 = Q2 = 1.60x10^-19C (Elementary charge)
r = given in the question (distance)

Note: The charge of a proton is equal to the charge of an electron except for the algebraic sign.

Answer 2

I tried that and got 1.8x10^8 but it wasn't the right answer

Answer 3

You didn't do it right. Just doing the orders of magnitude only..

F=E9*E-19*E-19/E-20 ( I squared the distance)
F=E(9-38+20) appx 10^-9 Newtons.

Answer 4

what does E mean? Could you explain it another way because I'm confused.