Asked by TOTALLY lost

The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 9 amperes when the resistance is 940 ohms. What is the current when the resistance is 580 ohms?

Thank you yet again. Almost through with this part of the class thank goodness!
Answered by Damon
i = k/r
9 = k/940
k = 8460

i = 8460/r
i = 8460/580
i = 14.6 amps

by the way, k is the voltage V
Answered by Henry
E = I*R = 9 * 940 = 8460 V. = Supply voltage.

I =E/R = 8460/580 = 14.6 Amps.
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