Question

For the gaseous reaction of carbon monoxide and chlorine to form phosgene, (COCl2), calculate each of the following.

(a) Calculate S° at 298 K
I got -136.76 J/K using delta S = sum of delta S of products minus sum of delta S of reactants which is the right answer.
But I can't figure out the second part:

(b) Assuming that S° and H° change little with temperature, calculate G° at 426 K.

In the standard thermodynamics values appendix it says the deltaH of COCl2 is -220 kJ/mol.

I am just not sure how to do this.

Answer 1

First, this is at 426K and not 298 K; therefore, any number you obtain by dGo = dHo - TdSo will not agree with 220 kJ/mol. So you substitute the values you have for dHo and dSo along with 426K for T and calculate dGo. Remember dH is given in kJ/mol and dS in J/mol.

Answer 2

DeltaG=DeltaH-DeltaS*T


Where

DeltaH=-220kJ/mol
DeltaS=-136.76kJ/K
T=426K
and
Delta=????

Answer 3

The key part of the equation states that ASSUME that DeltaS and DeltaH DOESN'T Change much, meaning that it is safe to plug and chug.


***To the questioner: change -136.76J/K to kJ, which should be -0.13676kJ/K

Answer 4

After reading Devron's reply I realize I read your initial question wrong. His response and mine agree; the only problem with mine is I thought you were quoting dG as -220 kJ/mol where you were quoting dH. Therefore, that part I wrote about "not agreeing with" make s no sense.

Answer 5

To the questioner: I apologize about the typos.

I meant to say solve for Delta*G and not just Delta. My post should have said the following:


DeltaG=DeltaH-DeltaS*T


Where

DeltaH=-220kJ/mol
DeltaS=-136.76J/K=-0.13676kJ/K
T=426K
and
DeltaG=???

Answer 6

I initially made the same mistake, which confused me a little. I reread the question and saw that the questioner and I, both, may have initially overthought the question.


--Best