Question

If 61.0 g of gaseous Cl2 and 25.4 mL of liquid CS2 are reacted stoichiometrically according to the balanced equation, how many milliliters of liquid CCl4 are produced?

CS2(l) + 3Cl2(g) → CCl4(l) + S2Cl2(l)

Answer 1

You will need the density of Cs2 and the density of CCl4.
Covert 61.0 g Cl2 to moles. mols = grams/molar mass.

Convert 25.4 mL CS2 to grams using the density of CS2. Convert g CS2 to mols.

Using the coefficients in the balanced equation, convert moles Cl2 to moles CCl4.
Using the coefficients convert moles CS2 to moles CCl4.
Likely the values for moles CCl4 will differ; the correct value in limiting reagent problems is ALWAYS the smaller value.

Convert moles CCl4 from the last step to grams. g = moles x molar mass. Now use the density to convert grams to volume.