Asked by Sarah

A gaseous mixture of O2 and N2 contains 31.8 % nitrogen by mass. What is the partial pressure of oxygen in the mixture if the total pressure is 445 mmHg?
Answered by bobpursley
The partial pressure of the gasses reflects the mole ratios of the gasses.

http://en.wikipedia.org/wiki/Partial_pressure

Assume 100grams of gas. 31.8 grams is N2, or the moles of N2 is 31.8/28=1.14
The moles of O2 will be 68.2/32=2.15

pressureN2/PressureO2 =
X/(445-x)=1.14/2.15

2.15x=1.14(445-x)
3.29x=507
pressureN2=154
pressureO2=291mmHg

check my work.
Answered by Sarah
your answer was correct!
Answered by bj
it looks complicated, but substitute your own numbers and follow his math process and it all works out for correct answer.
my P=825mmHg and 36.8% N2 was worked correctly.
Answered by Jim Crow
how high r u n cn I hav sum
Answered by Steve Woerner
I feel the chemistry between us ;)

Don't worry, I'm already measuring the noose...
Answered by OO_OO
So does this teacher just not read these like ever or is he a just smiling at all the attention he's getting
Answered by FNAF IS BETTER THAN FORTNITE
hello people from the past im in the futcure
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