if 225 ml of 0.25M HCL and 25ml of 2.5M NaOH was used what is the limiting reagent in this experiment?
2 answers
hi i don't know
I do these limiting reagent problems the long way.
HCl + NaOH ==> NaCl + H2O
mols HCl = M x L = about 0.056 but you need a better answer than that estimate.
That will produce 0.056 mols NaCl
mols NaOH = M x L = approx 0.0625.
That would produce approx 0.0625 mols NaCl.
In limiting reagent problems the smaller value ALWAYS wins and the reagent producing that value is the limiting reagent. That's HCl in this case.
HCl + NaOH ==> NaCl + H2O
mols HCl = M x L = about 0.056 but you need a better answer than that estimate.
That will produce 0.056 mols NaCl
mols NaOH = M x L = approx 0.0625.
That would produce approx 0.0625 mols NaCl.
In limiting reagent problems the smaller value ALWAYS wins and the reagent producing that value is the limiting reagent. That's HCl in this case.