Asked by Chase
Identify the correct statement for the following reaction:
Br2 (l) → Br2 (g) ΔH° = 30.9 kJ ΔS° = 93.2 J/K
A) The reaction is always spontaneous.
B) The reaction is never spontaneous.
C) The reaction is at equilibrium; therefore, ΔG° = 0.
D) The reaction could be spontaneous at high temperatures.
E) The reaction could be spontaneous at low temperature.
Br2 (l) → Br2 (g) ΔH° = 30.9 kJ ΔS° = 93.2 J/K
A) The reaction is always spontaneous.
B) The reaction is never spontaneous.
C) The reaction is at equilibrium; therefore, ΔG° = 0.
D) The reaction could be spontaneous at high temperatures.
E) The reaction could be spontaneous at low temperature.
Answers
Answered by
Devron
Used the following equation and plug in a couple of variables for T and see what you get.
ΔG=ΔH−TΔS
Remember, if ΔG is negative then the reaction is spontaneous, if positive, than the reaction is not spontaneous, and if equal to 0 is at equilibrium.
ΔG=ΔH−TΔS
Remember, if ΔG is negative then the reaction is spontaneous, if positive, than the reaction is not spontaneous, and if equal to 0 is at equilibrium.
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