Can you Identify the correct equilibrium constant, Keg, expression
2H2(g)+02(g)<->2H20(l)?
a)Keg=1/(2(H2)(02))
b)Keg=(H20)2/((H2)2(02))
c)Keg=1/(H2)2(02))
d)Keg=(H2)2(02)
1 answer
A is wrong
2H2(g)+02(g)<->2H20(l)?
a)Keg=1/(2(H2)(02))
b)Keg=(H20)2/((H2)2(02))
c)Keg=1/(H2)2(02))
d)Keg=(H2)2(02)
1 answer