Question
A block of weight 7.0N rest on a level floor. The frictional force between the block and the floor is 1.0N, A horizontal force of 1.4N is used to pull the block for 4s.what is the velocity of the block after this time?
Answers
Henry
M*g = 7 N.
M = 7/g = 7/9.8 = 0.71 kg
a = (Fap-Ff)/M = 1.4-1)/0.71=0.56 m/s^2
V = Vo + a*t = 0 + 0.56*4 = 2.24 m/s
M = 7/g = 7/9.8 = 0.71 kg
a = (Fap-Ff)/M = 1.4-1)/0.71=0.56 m/s^2
V = Vo + a*t = 0 + 0.56*4 = 2.24 m/s