Asked by Thomas
                Suppose f(x) = sin(pi*cosx) On any interval where the inverse function y = f –1(x) exists, the derivative of f –1(x) with respect to x is: 
a)-1/(cos(pi*cosx)), where x and y are related by the equation (satisfy the equation) x=sin(pi*cosy)
b)-1/(pi*sinx*(cos(pi*cosx))), where x and y are related by the equation x=sin(pi*cosy)
c)-1/(pi*siny*(cos(pi*cosy))), where x and y are related by the equation x=sin(pi*cosy)
d)-1/(cos(pi*cosy)), where x and y are related by the equation x=sin(pi*cosy)
e)-1/(siny*cos(pi*cosy)), where x and y are related by the equation x=sin(pi*cosy)
            
        a)-1/(cos(pi*cosx)), where x and y are related by the equation (satisfy the equation) x=sin(pi*cosy)
b)-1/(pi*sinx*(cos(pi*cosx))), where x and y are related by the equation x=sin(pi*cosy)
c)-1/(pi*siny*(cos(pi*cosy))), where x and y are related by the equation x=sin(pi*cosy)
d)-1/(cos(pi*cosy)), where x and y are related by the equation x=sin(pi*cosy)
e)-1/(siny*cos(pi*cosy)), where x and y are related by the equation x=sin(pi*cosy)
Answers
                    Answered by
            Thomas
            
    Inverse of sin(pi*cosx) = cos^(-1)((sin^(-1)(x))/pi)
Derivative of cos^(-1)((sin^(-1)(x))/pi) is
-1/(sqrt(1-x^2) sqrt(pi^2-sin^(-1)(x)^2))
    
Derivative of cos^(-1)((sin^(-1)(x))/pi) is
-1/(sqrt(1-x^2) sqrt(pi^2-sin^(-1)(x)^2))
                    Answered by
            Thomas
            
    derivative: sin(pi*cosx) = -pi sin(x) cos(pi cos(x))
    
                    Answered by
            Thomas
            
    It was B
    
                    Answered by
            Hector Ramos
            
    If anything it wasn't B because I have put in the answer for B and it didn't work. It must be A, C, D, or E instead.
    
                    Answered by
            purple
            
    for others who need help the answer is -1/(pi(siny(cosy) the with respect to x messed me up. 
    
                    Answered by
            Megan
            
    Which one is that? I don't think that's an option
    
                    Answered by
            May
            
    Its c
    
                    Answered by
            Phia
            
    Its -1/pi(sinycos(picosy) where x and y are related by the equation x=sin(picosy) 
    
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