Asked by Anonymous
Th integral of tan(3x)dx
Answers
Answered by
Reiny
tan (3x) = sin(3x)/cos(3x)
so ∫tan(3x) dx
= ∫sin(3x)/cos(3x) dx
= -(1/3) ln(cos(3x)) + c
so ∫tan(3x) dx
= ∫sin(3x)/cos(3x) dx
= -(1/3) ln(cos(3x)) + c
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