Question
a ball was thrown vertically upward from the ground and reaches a height of 50 meters. a) with what speed was it thrown?
b) how long will it remain in the air?
b) how long will it remain in the air?
Answers
since h(t) = vt - 4.9t^2, the vertex is at t = v/9.8
so,
v(v/9.8) - 4.9(v/9.8)^2 = 50
v = 31.305 m/s
Now you can find how long it was in the air. Namely, twice as long as it took to reach its max height.
so,
v(v/9.8) - 4.9(v/9.8)^2 = 50
v = 31.305 m/s
Now you can find how long it was in the air. Namely, twice as long as it took to reach its max height.
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