Asked by abd
Ball A is thrown vertically upwards with a velocity of 30m/s from the ground. After 3 seconds ball B is also thrown vertically upwards with a velocity of 50m/s from the ground. Determine the time at which ball A and B will meet in air.
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Answered by
Steve
what step by step? The same equation (h = vt - g/2 t^2) applies to both balls, so just set them equal:
30t-4.9t^2 = 50(t-3) - 4.9(t-3)^2
http://www.wolframalpha.com/input/?i=30t-4.9t%5E2+%3D+50(t-3)+-+4.9(t-3)%5E2
30t-4.9t^2 = 50(t-3) - 4.9(t-3)^2
http://www.wolframalpha.com/input/?i=30t-4.9t%5E2+%3D+50(t-3)+-+4.9(t-3)%5E2
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