Asked by danny
You need to determine the pKa of a weak, monoprotic acid. You add 0.500 moles of the acid to 1.00 L of water. The resulting pH was 1.87. What is the pKa of this weak acid? You may ignore the autoionization of water.
2.74
3.43
5.38
2.01
1.87
2.74
3.43
5.38
2.01
1.87
Answers
Answered by
DrBob222
......HA ==> H^+ + A^-
I.....0.5....0......0
C.....-x.....x......x
E...0.5-x....x......x
Enter the E line into Ka expression and solve for Ka. The problem tells you the pH which will give you the (H^+) and (A^-). Then convert to pKa.
I.....0.5....0......0
C.....-x.....x......x
E...0.5-x....x......x
Enter the E line into Ka expression and solve for Ka. The problem tells you the pH which will give you the (H^+) and (A^-). Then convert to pKa.
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