Asked by Anonymous
How do I: a.) find the energy in a 3.50x10^-5f parallel plate capacitor if it holds 2.00x10^-3c of charge
b.)find the voltage between the plates
c.)determine the new voltage after doubling the stored energy
b.)find the voltage between the plates
c.)determine the new voltage after doubling the stored energy
Answers
Answered by
Henry
a. Q = C*V
Solve for V.
Energy = C*V^2/2
b. Calculated V in part a.
c. To double the stored energy, multiply
V by the square root of 2:
The new voltage = sqrt(2) * V.
Solve for V.
Energy = C*V^2/2
b. Calculated V in part a.
c. To double the stored energy, multiply
V by the square root of 2:
The new voltage = sqrt(2) * V.
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