Asked by Anonymous

How do I: a.) find the energy in a 3.50x10^-5f parallel plate capacitor if it holds 2.00x10^-3c of charge
b.)find the voltage between the plates
c.)determine the new voltage after doubling the stored energy

Answers

Answered by Henry
a. Q = C*V
Solve for V.

Energy = C*V^2/2

b. Calculated V in part a.

c. To double the stored energy, multiply
V by the square root of 2:

The new voltage = sqrt(2) * V.


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