Asked by John
Find the energy stored in the solid flywheel of mass 8.0×104 and radius 1.8 when it's rotating at 290
Answers
Answered by
Joshua
Kr=1/2*(I*w^2)
I=1/2*(M*R^2)
w=(290*2pi)/60
Kr=1/2((290*2pi)/60)^2*(.5*8.0*10^4*1.8^2)
Kr=~~~(whatever that equals my question was different just be glad i did this at all ahah)
(this is all assuming you mean 10^4 and 290 is in rpm)
I=1/2*(M*R^2)
w=(290*2pi)/60
Kr=1/2((290*2pi)/60)^2*(.5*8.0*10^4*1.8^2)
Kr=~~~(whatever that equals my question was different just be glad i did this at all ahah)
(this is all assuming you mean 10^4 and 290 is in rpm)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.