Question

I'm having some torubles understanding these question.

<i>Sketch y1 = x-3 and y2 = 1/x-3 on the same set of axis</i>

<b>a) What is the relationship between the zero of y1, and vertical asymptote of y2?</b>

Does the question mean when y1 = 0?. I know the vertical asymptote is just a vertical line on the graph that gets closer and closer and closer to, but doesn't actually touch.

c)When y1 has a large positive value, explain what happens to the value of y2. Similarly, when y1 has a large negative value what happens to y2? Explain why this happens.

I know if the y1 value gets larger, so does the x value. But how does y1 having a large value even affect the value of y2, when they're both different graphs.

I appreciate any help. Thanks.

Answer 1

a) y1 = 0 at x = 3. The asymptote of y2 is a vertical line at x = 3.

(c) When y1 has a large negative value, you are in the region of large negative x. In that same region, y2 approaches 0 asymptotically from below the x axis.

Answer 2

I wrote y2 wrong
It's suppost to be y2 = 1/(x-3)

Answer 3

That is what I assumed you meant. My answer remains the same

Answer 4

Note corrected subject spelling

Answer 5

How many 3/4 are in 3?

Answer 6

well you see i don't know

Answer 7

just divide 3 by .75:

3/.75=???
4