Asked by Zee
A woman is attached to a bungee cord from a bridge that is 38m above a river. Her height in meters above the river t seconds after the jump is y(t)=19(1 + e^-1xcos(t)) for t>0.
What is her velocity at t=1 and t=4?
What is her velocity at t=1 and t=4?
Answers
Answered by
bobpursley
I am wondering what the x variable is? or is that times?
Answered by
Zee
t=0 initially
Answered by
Steve
I assume you meant
y(t) = 19(1+e^(-cos(t))
so,
v(t) = 19sin(t) e^(-cos(t))
v(1) = 19 sin(1) e^-cos(1) = 9.31
v(4) = 19 sin(4) e^-cos(4) = -27.64
y(t) = 19(1+e^(-cos(t))
so,
v(t) = 19sin(t) e^(-cos(t))
v(1) = 19 sin(1) e^-cos(1) = 9.31
v(4) = 19 sin(4) e^-cos(4) = -27.64
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