Question
A 300 lb bungee jumper wants to jump from the top of a 230 ft high bridge and be able to just touch the water below (Part A figure) . Given that the bungee cord has a spring constant of 11.1 lb/ft, what should the bungee cord's relaxed length, l, be for this jump?
Answers
cord potential energy at maximum allowed extension = potential energh loss of jumper, at the bottom
(1/2)k(230-L)^2 = M*g*230
Solve for L.
k is the spring constant.
Mass must be in slugs, or use M*g = 300 lb.
(1/2)k(230-L)^2 = M*g*230
Solve for L.
k is the spring constant.
Mass must be in slugs, or use M*g = 300 lb.
Related Questions
A bungee jumper is standing at the edge of a platform, just about to leap over the side. Midway thro...
A bungee jumper falls for 1.3 seconds before the bungee cord begins to stretch. Until the jumper ha...
When you bungee jump,you are falling under free fall untill you reach the end of the elastic rope bu...
A bungee jumper of mass 75 kg uses a bungee cord with a relaxedlength of 50 m and jumps from a bridg...