Asked by Cassandra
The line that passes through (4,3r) and (2+r,-6) is perpendicular to the line with equation 5x+3y+12=0. find r.
Answers
Answered by
Steve
5x+3y+12=0 has slope -5/3
So, our desired line has slope 3/5
(-6-3r)/(2+r-4) = 3/5
Now find r.
So, our desired line has slope 3/5
(-6-3r)/(2+r-4) = 3/5
Now find r.
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