Asked by Sarah

Line m passes through (2,5) and (-3,-2) Find the slope of a line that is perpendicular to line m.
Answered by Steve
line m has slope ∆y/∆x = (-2-5)/(-3-2) = 7/5

the perpendicular line's slope is the negative reciprocal, or -5/7
Answered by Kuai
m = (-2-5)/(-3-2)
m = 7/5

Perpendicular m = -5/7

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