Asked by Anonymous

The integral of sin(7x)cos(7x)dx
Answered by Steve
your expression is just 1/2 sin(14x) dx
Answered by jaykim
Let u=7x du/dx=7 du/7=dx therefore,1/7integral sinucosudu let v=sinu dv/du=cosu du=dv/cosu: 1/7intergralvdv=1/7v^2/2=1/14sin^2(7x)
There are no AI answers yet. The ability to request AI answers is coming soon!