Asked by danny
The enthalpy change for the following reaction is -483.6 kJ:
2H2(g) + O2(g) = 2H2O(g)
Therefore, the enthalpy change for the following reaction is _______ kJ: 4H2(g) + 2O2(g) = 4H2O(g)
Answers
Answered by
DrBob222
You have doubled the reaction; wouldn't the new enthalpy change be just twice as much.
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