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What is the change of enthalpy associated with the combustion of one mole of pentane?

C5H12 + 8O2 �¨ 5CO2 + 6H2O
I'm very confused, Please help!

1 answer

C5H12 + 8O2 ==> 5CO2 + 6H2O
dHrxn = (n*dHf products) - (n*dHf reactants).

Look up the heat formation of the products and reactants, plug into the above and solve for dHrxn.
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