Question

What is the change of enthalpy associated with the combustion of one mole of pentane?
C5H12 + 8O2 ¨ 5CO2 + 6H2O
I'm very confused, Please help!
C5H12 + 8O2 ==> 5CO2 + 6H2O
dHrxn = (n*dHf products) - (n*dHf reactants).

Look up the heat formation of the products and reactants, plug into the above and solve for dHrxn.

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