Asked by chem_01
Enthalpy Change
Given the following reactions:
S(s) + O2(g) → SO2(g) ΔH = -297 kJ/mol
SO2(g) + ½ O2(g) → SO3(g) ΔH = -141 kJ/mol
Calculate the ΔH for the reaction:
S(s) + 3/2O2(g) → SO3(g)
Given the following reactions:
S(s) + O2(g) → SO2(g) ΔH = -297 kJ/mol
SO2(g) + ½ O2(g) → SO3(g) ΔH = -141 kJ/mol
Calculate the ΔH for the reaction:
S(s) + 3/2O2(g) → SO3(g)
Answers
Answered by
..........
ΔH= (-297)+ (-141)
-438kJ/mol
-438kJ/mol
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