Asked by Sandra

A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = –0.02x2 + 2.3x + 6, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? My mind is blank...
57.50 m
115.00 m
117.55 m
235.10 m
Answered by Steve
it lands when the height (y) is zero. So, just solve for x in

-0.02x2 + 2.3x + 6 = 0

just use the quadratic formula.
Answered by DingDong
Its 117.55 ^^
Answered by raychelz
bro thanks
Answered by ice spice
i guess it still works for the future highschool students 2023,2024,2025,2026,2027,2028,2029
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