Asked by bill
A fire engine must lift 30 kg of water a vertical distance of 20 m each second. What is the amount of power needed for the water pump for this fire hose?
P=W/t=Fd/t=mgd/t
(30)(9.8)(20)/1= 5880 W
is that right?
P=W/t=Fd/t=mgd/t
(30)(9.8)(20)/1= 5880 W
is that right?
Answers
Answered by
bobpursley
yes.
Answered by
Anonymous
-fire-engine-must-lift-30-kg-of-water-a-vertical-distance-of-20-m-each-second-what-is
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