Question

A fire engine’s water tank holds 750 gallons of water. If the pump removes 250 gallons of water in 5 minutes, what is the change in the amount of water in gallons in 1 minute?(1 point)
Responses

15
15

−50
negative 50

50
50

−15

Answer 1

Use the properties of operations and rules for multiplying and dividing signed numbers to solve:

(−4)×(7/5)×(−3/4)÷(7/15)

(1 point)

Answer 2

Solve the following word problem. A fish is swimming at −10.8 meters, or 10.8 meters below sea level. Every 2 minutes it descends another 1.5 meters. How long will it take for the fish to reach a depth of −37.8 meters? Show your work and write a sentence to explain what your answer means.(4 points)

Answer 3

To find the change in the amount of water in one minute, we need to divide the amount of water removed in 5 minutes by 5.

250 gallons / 5 minutes = 50 gallons/minute

Therefore, the change in the amount of water in gallons in 1 minute is 50.

Answer 4

To simplify the expression, let's solve it step by step:

First, let's multiply the signed numbers:

(-4) * (-3) = 12

Next, let's multiply the fractions:

(7/5) * (7/15) = 49/75

Finally, let's divide the result of the multiplications:

12 * (49/75) = 588/75

So, the simplified expression is 588/75.

Answer 5

To solve this problem, we need to find out how many 2-minute intervals it will take for the fish to reach a depth of -37.8 meters.

First, let's find out the difference in depth between the starting point (-10.8 meters) and the target depth (-37.8 meters):

-37.8 meters - (-10.8 meters) = -37.8 meters + 10.8 meters = -27 meters

The fish descends at a rate of 1.5 meters every 2 minutes. To find out how many 2-minute intervals it will take for the fish to reach a depth of -27 meters, we divide -27 meters by 1.5 meters:

-27 meters ÷ 1.5 meters = -18

So, the fish will take 18 intervals or 36 minutes (18 x 2 = 36) to reach a depth of -37.8 meters.

This means that it will take the fish 36 minutes to swim down to a depth of -37.8 meters below sea level.